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Hello and welcome to the goal and programming language course in the previous session, we talked about

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sending a into a function in goal.

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And in this session, we want to talk about the other's point first concept.

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Comparing pointers in gold and in gold language, you are allowed to compare two pointers with each

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other.

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Two pointers values are only equal, then they point to the same value in the memory or if they are

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needed, you can perform a conversion on pointers with the help of equal two and not equal to operators

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provided by the gold language.

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Now you can see the syntax go to this good program and illustrate how to use competing pointers in gold

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language.

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First, create an initialized to actual variable for the example, value one column equals 100.

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And the next line value two equals 200.

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Now create three pointers and initialize them by the address of allow variables.

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For the example, P1 call equals person value one and P2 calling equals ampersand value.

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Two and P3 column equals ampersand again.

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Value one.

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Now, compare two pointers together and put the result as a Boolean value in a valid for the example

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he compared to pointers P one and P two and set results in the result more valuable.

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Now do the following result long column equals p one equal to p to.

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By this quote, we can compare to variable and set result in another value the display.

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The result of this conversion FP

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result from.

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He's.

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P. Long, equal

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and assets, the result one.

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So let's do a few more conversions for the example, conversion between P1 and P3 now write results

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to calling equals P1 equal to P3 and display the result if be resolved to these P1 equals.

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P three and sit to resolve to leave it to other competition for the example, competition between P2

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and P3 resolved three Kollin equals P2 equal to P3 display the result FP resolved three E's P two equal

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P three and set the result three rated here.

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OK.

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We will now compare the addresses of the -- to available together, for the example addresses of two

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pointers of Pilon and P. to define resolved for call and he calls and some p for equal to Anderson P

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three and display the result for FP Zonked for.

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He's P one, equal P three and set the result for here.

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Vom and PETA.

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And the other condition, for example, competition between P1 and P2 resolved fight calling equals

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nine percent P1 equal to Anderson P two and especially the result five if P result five is P1 equaled

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P2 asset, the variable result five.

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And another conversion for the example between P2 and P3 result six current equals countersign p to

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equal to Anderson P3 and display the result.

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FP results six is P2 equal P3 and set the result six variable here.

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Now reformat the code, save the project and execute the program.

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Now we can see outputs in all these competitions.

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Only the variable Piven is equal to P3 and in the regional two variable, the answer to is sort for

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us.

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And the other countries are not equal to each other and show us the false answer in order not to prolong

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the time of decision.

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You will finish it and we will continue the content in the next session.

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Goodbye.